$$ \mu_A^(l) = \mu_A^(g) $$
$$ \mu_A^(l) = \mu_A^{\circ}(g) + RT\ln{p_A^} $$
$$ \begin{align*} \mu_A(l) &= \mu_A(g)
\\
\mu_A(l) &= \mu_A^{\circ}(g) + RT\ln{p_A} \end{align*} $$
E a mudança no potencial químico de $A$ na fase líquida é contabilizada pela subtração:
$$ \begin{align*} \mu_A(l)-\mu_A^(l) &= \mu_A^{\circ}(g) + RT\ln{p_A} - \mu_A^{\circ}(g) - RT\ln{p_A^}
\\
\mu_A(l) & = \mu_A^(l) + RT\ln{\dfrac{p_A}{p_A^}} \end{align*} $$
$$ \boxed{\dfrac{p_A}{x_A} = p_A^*} $$
<aside> <img src="https://prod-files-secure.s3.us-west-2.amazonaws.com/8ae9c6af-5fb5-44bd-84ad-e1b5b86abbce/591eb02c-d28d-490b-bc09-258519db535f/Designer_(2).png" alt="https://prod-files-secure.s3.us-west-2.amazonaws.com/8ae9c6af-5fb5-44bd-84ad-e1b5b86abbce/591eb02c-d28d-490b-bc09-258519db535f/Designer_(2).png" width="40px" /> A Lei de Raoult
$$ \boxed{p_A = p_A^*x_A} $$
</aside>
<aside> <img src="https://prod-files-secure.s3.us-west-2.amazonaws.com/8ae9c6af-5fb5-44bd-84ad-e1b5b86abbce/591eb02c-d28d-490b-bc09-258519db535f/Designer_(2).png" alt="https://prod-files-secure.s3.us-west-2.amazonaws.com/8ae9c6af-5fb5-44bd-84ad-e1b5b86abbce/591eb02c-d28d-490b-bc09-258519db535f/Designer_(2).png" width="40px" /> A Lei de Raoult
$$ \boxed{\mu_A(l) = \mu_A^*(l) + RT\ln{x_A}} $$
</aside>